10100011 10001001 11011101 11100111 in my 1st row 001 2nd row m 1 from left most 2nd and 3rd culom 00 from left are abrupted in example 9.4 of lect 34, by applying even parity it ans come 10010010 but in handouts it ans is 10101010 LRC that is confusing me pls explain
There should be no confusion regarding this because we mentioned the same LRC over there which we calculated before the bits get corrupted / altered. Just for matching propose.
In other words, the same LRC has been mentioned there, just for matching.
Please re-calculate the LRC of following block of bits in which some bits are corrupted.
10100011
10001001
11011101
11100111
__________
Then match your result with 10101010 which is the LRC calculated before the bits get corrupt.
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